Question 429134
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Hi
z^2-5z-6=0    |Note the use of ^ (uppercase 6)
{{{z = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}   az^2 + bz + c = 0
{{{z = (5 +- sqrt( 49 ))/(2) }}}
   {{{z = (5 +- 7)/(2) }}}
     z = 12/2 = 6  OR z =-2/2 = -1

CHECKING our Answer(s)***
  36-32-6 = 0        when z = 6
  1 -5*-1 - 6 = 0    when z = -1