Question 429149
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Hi
 length exceeds the width by 28 inches.
Let x and (x+28in)represent the width and length respectively
 2(x+28) + 2x = 68in
  4x = 12in 
   x = 3in, the width.  the length is  31in  (3in + 28in)

CHECKING our Answer***
  2*31in + 2*3in =  62in + 6in = 68in
<img src="http://upload.wikimedia.org/wikipedia/commons/thumb/d/da/PerimeterRectangle.svg/200px-PerimeterRectangle.svg.png">