Question 429122
x^2+1=-2x
x^2+2x+1=0
(x+1)(x+1)=0
.
To find 'x', set (x+1) to zero and solve:
x+1 = 0
x = -1
.
To check, plug back into original equation:
x^2+1=-2x
(-1)^2+1=-2(-1)
1+1 = 2
2 = 2 (checks)