Question 429092
Just use the fact that {{{(a^b)^n = a^(bn)}}}. Here, we have


{{{3^(4x+2) = 9^(x-1) = (3^2)^(x-1) = 3^(2x-2)}}}. The exponents must be equal, so we set 4x+2 equal to 2x-2 and solve.


{{{4x+2 = 2x-2}}}

{{{2x = -4}}}

{{{x = -2}}}.