Question 428603
{{{(5x - 10)/(x^2 + x - 6)}}}
-------------
{{{(2x^2 + x -6)/(2x^2 + 5x -12)}}}
:
Invert the dividing fraction and multiply
{{{(5x - 10)/(x^2 + x - 6)}}} * {{{(2x^2 + 5x -12)/(2x^2 + x -6)}}}
:
Factor
{{{(5(x - 2))/((x+3)(x-2))}}} * {{{((2x-3)(x+4))/((2x-3)(x+2))}}}
:
Cancel (2x-3)
{{{(5(x - 2))/((x+3)(x-2))}}} * {{{((x+4))/((x+2))}}}
:
Cancel (x-2)
{{{5/((x+3))}}} * {{{((x+4))/((x+2))}}} = {{{5(x+4)/((x+3)(x+2))}}} or {{{(5x+20)/((x^2+5x+6))}}}