Question 428673
Solution:First we set the equation to zero:

{{{3y^2+5y+2=0}}} Using the Quadratic Formula we have:

{{{y=(-5+-sqrt(25-24))/6}}}

{{{y=(-5+-sqrt(1))/6}}}, y=-5+1/3=-4/6=-2/3 and y=-5-1/6=-6/6=-1

Answer: The solution set is {-1,-2/3}