Question 428650
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Hi
one leg of a triangle is 7 ft longer than other leg
Let x and (x+7)represent th elengths of the two legs respectively
 a² + b² = c² 
 x^2 + (x+7)^2 = 13^2
 2x^2 + 14x -120 = 0
 x^2 + 7x - 60 = 0
(x + 12)(x-5) = 0
(x + 12)=0  x = 12  |tossing out negative solution for length
 (x-5) = 0
  x = 5, the other side is 12  (5+7)

 CHECKING our Answer***
 25 + 144 = 169 = 13^2