Question 426834
Let's call x the smaller number and y the larger number.
So we have {{{x+y=27}}} and {{{5x=3y-1}}}
Now rearrange the first equation to say {{{y=27-x}}} and substitute into the second equation. {{{5x=3*(27-x)-1}}} -> {{{5x=81-3x-1}}} -> {{{8x=80}}} -> {{{x=10}}}
Now that we have {{{x}}} plug into {{{5x=3y-1}}} to get {{{5*10=3*y-1}}} 50+1=3*y}}}-> {{{51=3*y}}} -> {{{17=y}}}
So your ordered pair is (10,17)