Question 428622
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Substitute *[tex \Large \frac{\sin^2\theta}{\cos^2\theta}] for *[tex \Large \tan^2\theta], and substitute *[tex \Large \frac{\sin^2\theta}{1}] for *[tex \Large \sin^2\theta].


Invert and multiply, leaving you with *[tex \Large \frac{1}{\cos^2\theta}].  Then, recalling that the secant is the reciprocal of the cosine, finish by saying *[tex \Large \sec^2\theta]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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