Question 428578
{{{(x^2-6x+5)/(2x^2+5x-7)}}}
The expression can be factored as:
{{{(x-5)(x-1)/(2x+7)(x-1)}}} This can checked by FOIL multiplication.
The factor {{{x-1}}} cancels and we are left with:
{{{(x-5)/(2x+7)}}}