<PRE><B>Question 44950</B>
d/(d^2)-9)+5/2d+6

d/[(d-3)(d+3)]+ 5/[2[(d+3)]

LCD=(d-3)(d+3)

d/LCD + 5(d-3)/LCD

Add the numerators to get:

[d+5d-15]/LCD
[6d-15]/[(d-3)(d+3)]
Cheers,
Stan H.






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