Question 428350

three consecutive integers are  x,  x+1  and  x+2.


x*(x+2) - (x+1) = 1+ 7(x+2)

=> x^2 + 2x - x -1 = 1 + 7x + 14

=> x^2 -6x -16 = 0

=>  x^2 -8x  + 2x -16 = 0

=> x(x-8) +2(x -8) = 0

=> (x+2)(x-8) =0

so, x=8 and x = -2 (not positive integer)

numbers are  8, 9 and 10.