Question 428284
A normal distribution has a mean of 52 and a standard deviation of 4.2 What is the probability of a value between 44.0 and 55.0? 
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z(55) = (55-52)/4.2 = 0.7143
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P(44<= x <=55) = P(-1.9048<= z <= 0.7143) 
= normalcdf(-1.9048,0.7143) = 0.7341
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Cheers,
Stan H.
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