Question 428314
A child's bank contains nickels dimes and quarters. 
There are three times as many nickels as dimes 
and there are five more quarters than nickels. 
The total value of the coins in the bank is $6.25. 
Find the number of each type of coin. 
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Equation:
n = 3d
q = n+5
5n + 10d + 25q = 625
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Solve for d and n:
d = (1/3)n
q = n+5
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Substitute and solve for "n":
5n + 10(1/3)n + 25(n+5) = 625
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5n + (10/3)n + 25n+125 = 625
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(30+(10/3))n = 500
(90+10)n = 1500
n = 15 (# of nickels)
d = (1/3)n = 5 (# of dimes)
q = n+5 = 20 (# of quarters)
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Cheers,
Stan H.
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