<PRE><B>Question 428272</B>
A vintage car leaves Des Moines,Iowa traveling at the rate of 45 miles per hour.
One hour later a faster car sets out from the same town to overtake the first.
At what rate must the faster car travel in order to overtake the first in 5 hours?
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Faster Car DATA:
time = 5 hrs; rate = x mph ; distance = 5x miles
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Vintage DATA:
rate = 45 mph ; time = 6 hrs: distance = rt = 6*45 = 270 miles
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Equation:
distance = distance
5x = 270
x = 54 mph (rate of the faster car) 
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Cheers,
Stan H.
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