Question 428228
{{{ 3x-(5-4x)=2(4x+2)+1 }}}
{{{ 3x - 5 + 4x = 8x + 4 + 1 }}}
{{{ 7x - 5 = 8x + 5 }}}
Now subtract {{{7x}}} from both sides
{{{ -5 = x + 5 }}}
Subtract {{{5}}} from both sides. This is the same
 as adding a {{{-5}}} to both sides
{{{ -10 = x }}} answer
You can do a check by plugging this back
into original equation:
{{{ 3x-(5-4x)=2(4x+2)+1 }}}
{{{ 3*(-10) - (5-4*(-10))=2(4*(-10)+2)+1 }}}
Now work from the inside of the parentheses outward
{{{ -30 - (5 - 4*(-10))=2(-40+2)+1 }}}
{{{ -30 - (5 + 40) = 2*(-38) +1 }}}
{{{ -30 - 45 = -76 + 1 }}}
{{{ -75 = -75 }}}
OK