Question 428161
Given the quadriatic function f(x) = x^2 - 14x + 49, find the value of x such that f(x) = 36
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Set f(x) to 36 and solve for x:
36 = x^2 - 14x + 49
0 = x^2 - 14x + 13
0 = (x-13)(x-1)
x = {1, 13}