<PRE><B>Question 428099</B>
what is the equation of the line that has a slope of 4 and passes through the point (3,-10)?

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The equation that you need to find is y = mx + b where m is the slope and (0,b) is the y-intercept.

The slope is given which is m = 4 and a point (3, -10)

Then you can use slope-point  equation (review your textbook)

y - yo = m(x - xo) where (xo,yo) is the given point
y - (-10) = 4(x - 3)
y + 10 = 4x - 12
y = 4x - 22

This is the line that you need to find!John10
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