Question 428046
Solution:Use the well known formula: {{{a^3+b^3=(a+b)(a^2-ab+b^2)}}}

where {{{a^3=64x^3=(4x)^3}}}

and   {{{b^3=1=1^3}}},after substituting we have:

{{{64x^3+1=(4x)^3+1^3=(4x+1)(16x^2-4x+1)}}}

Done.