Question 427989
Let h be the time
Passenger train: d = s*t = 105(h-5)
Freight train: d = s*t = 70h

The distance is the same: 105(h-5) = 70h

105h - 525 = 70h
35h = 525
h = 525/35
h = 15

Substitute h = 15 into either above distance equation to find the distance

Hope it will help you! John10