Question 427715
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Hi

{{{(3y+3)/(y^2-4y-5) + (2y+2)/(y^2-2y-3)}}}
Am factoring y^2-4y-5 = (y-5)(y+1)  AND y^2-2y-3 = (y-3)(y+1) FIRST
 {{{3/(y-5) + 2/(y-3)}}}
 {{{(3(y-3)+2(y-5))/(y-5)(y-3))}}}
 {{{(5y-19)/(y-5)(y-3))}}}