Question 427637
Solution:Since the zeros of the function are:-2, 1, and 3 the cubic function will be:
    {{{f(x)=(x+2)(x-1)(x-3)=(x^2+x-2)(x-3)=x^3-2x^2-5x+6}}}

The value of this function for x=6 is f(6)=120. The problem request to find a function that g(6)=8, 8=120-112, therefore the requested function will be:

{{{g(x)=x^3-2x^2-5x-106}}}, where g(6)=8.