Question 427584
Ok again I am stumped by this ; Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14

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 -2x-7y=-14
convert to standard form, y=mx+b, m=slope and b=y-intercept
7y=-2x+14
 y=(-2/7)x+2
 slope =-2/7
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slope of equation perpendicular to first equation is equal to its negative reciprocal=7/2
Equation:
y=mx+b
using point (-8,-11) to solve for b
-8=(7/2)(11)+b
-16=77+2b
-93=2b
b=93/2
Equation of line:
y=(7/2)x+93/2 (ans)
see graph of these two lines below:Note the slopes of the two lines

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{{{ graph( 300, 200, -20, 10, -10, 10, (-2/7)x+2,(7/2)x+93/2) }}}