Question 427491
Solution: The center of circle is: X0=2+2/2=2 and Y0=-7+1/2=-3, center is (2,-3)
and 
{{{ d= sqrt ((2-2)^2+(1+7)^2)}}}, d=8 and r=4 As we know the equation of circle

Centered at (X0,Y0) and radius r is: {{{(X-X0)^2+(Y-Y0)^2=R^2}}}

Substituting our given results: {{{(x-2)^2+(y+3)^2=16}}} is the equation of circle.