Question 427470
We know the standard equation for the circle is:
(x - h)^2 + (y - k)^2 = r^2 where (h,k) is the center and r is the radius
Substitute the center (h,k)=(0,2) and r = SR(6)
(x - 0)^2 + (y - 2)^2 = ((SR(6))^2
x^2 + y^2 - 4y + 4 = 6
x^2 + y^2 - 4y = 2
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