Question 427425
Write the slope-intercept equation for the line that passes through (-12, 10) and is perpendicular to 4x + 6y = 3 

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First find the slope of the given line:

Write the equation i slope-intercept form: y = mx + b

4x + 6y = 3
6y = -4x + 3
y = (-2/3)x + 1/2

Since the given line is perpendicular with the new line, their slopes product is -1.

Let m be the slope of the new line: (-2/3)m = -1

m = -1 * (-3/2) = 3/2

Now we use the slope m = 3/2 and (-12, 10) to find the equation

y -10 = 3/2 (x +12)

y -10 = (3/2)x + 18

y = (3/2)x + 28

This is the line that we need to find!Hope it will help you!