Question 427407
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Hi
x^2+4y^2-6x+8y+9=0   
(x-3)^2 -9 + 4[(y+1)^2 -1] + 9 = 0
(x-3)^2 -9  + 4(y+1)^2 -4 + 9 = 0
(x-3)^2 + 4(y+1)^2 = 4
{{{(x-3)^2/4 + (y+1)^2/1 = 1 }}}  Ellipse