Question 427363
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Hi
{{{sqrt(x-2) = x-4)}}}   |Squaring both sides of the Equation
    x-2 = x^2 - 8x + 16
   x^2 -9x + 18 = 0
factoring
 (x-3)(x-6) = 0 Note:SUM of the outside terms(-6x) and the inside terms(-3x) = -9x
 (x-3)= 0    x = 3  |Tossing out: sqrt(1) &#8800; -1
 (x-6) = 0   x = 6
It is always recommended to 'check out' the solutions found in the original EQ