Question 427271
Solve:{{{3-(a-(6/a)+5)=(a^2-(14/a)+5)}}}

{{{3-a+(6/a)-5=a^2-(14/a)+5}}} Considering -a- different of 0, multiply both sides of equation by a:

{{{3a-a^2+6-5a=a^3-14+5a}}} Combine like terms:

{{{a^3+a^2+7a-20=0}}}, This equation is irreducible.

From its graph an approximate root is at interval (1,2), {{{1<=a<=2}}}

{{{graph(600, 600, -5, 5, -25, 5, x^3+x^2+7x-20)}}}