Question 427266
i'm assuming you want to simplify this as much as possible.


you are starting off with {{{(root(5,2x^2y))^3}}}


{{{root(5,2x^2y)}}} is the same as {{{(2x^2y)^(1/5)}}}


your expression becomes:


{{{((2x^2y)^(1/5))^3}}}


since, in general, {{{(a^b)^c = a^(b*c)}}}, then your expression becomes:


{{{(2x^2y)^(3/5)}}}


singe, in general,


{{{(a^b*c^d*e^f)^g = a^(b*g)*c^(d*g)*e^(f*g)}}}, then your expression becomes:


{{{2^(3/5)*(x^2)^(3/5)*y^(3/5)}}}


this simplifies to:


{{{2^(3/5)*x^(6/5)*y^(3/5)}}}


if you can't see it because it is cut off, the exponent over the 2 is 3/5, and the exponent over the x is 6/5 and the exponent over the y is 3/5.


i have confirmed that the original expression and the final expression are equivalent.


if that's what you were asking about, then this should be your answer.