Question 44838
{{{(x-1)/(x+1) - 2/(x^2+x) }}}
Notice that {{{x^2+x=x(x+1)}}}
So:
{{{(x-1)/(x+1) - 2/(x^2+x) =(x-1)/(x+1) - 2/x(x+1) }}}
Now multiply top and bottom of the first fraction by x:
{{{(x(x-1))/(x(x+1)) - 2/(x(x+1))}}}
And simplify:
{{{(x(x-1)-2)/(x(x+1)) }}}
{{{(x^2-x-2)/(x(x+1)) }}}
Factorise the top:
{{{((x+1)(x-2))/(x(x+1)) }}}
The (X+1)'s cancel so:
{{{(x-2)/x }}}
Theres your answer. Dude!
I hope this helps.
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
Adam