Question 427129
Solve the equation.

9x = 3x^3
3x^3 - 9x = 0 {subtracted 9x from both sides}
3x(x^2 - 9) = 0 {factored 3x out}
3x(x + 3)(x - 3) = 0 {factored x2 - 9 into two binomials}
3x = 0 or x + 3 = 0 or x - 3 = 0 {set each factor equal to 0}
x = 0 or x = -3 or x = 3 {solved each equation for x}
x = 0,-3, or 3
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