Question 427100
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
The height of the arrow is given by the function h(t)=-16t^2+64t+34, 
where t is the time in seconds. What is the maximum height of the arrow?
-16t^2+64t+34    |parbola opening downward, completing the square to find vertex
h(t)=-16t^2+64t+34,
h(t)=-16(t-2)^2 + 64 +34
h(t)=-16(t-2)^2 + 98   |Vertex(2,98)
  98ft is the maximum height of the arrow

{{{drawing(300,300,  -100,100,-100,100,   blue(line(2,100,2,-100))  , grid(1),
graph( 300, 300, -100,100,-100,100,  0, -16x^2+64x+34))}}}