Question 427061
Solution:First we simplify the system dividing the first equation by 2 and the second by 4,and the system can be written:

{{{system(x+2y=6, x+4y=2)}}}, Express x in the first equation with respect to y and substitute in the second equation:

{{{system(x=6-2y, 6-2y+4y=2)}}}

The second equation is a linear equation of one variable. We solve this equation with respect to y:

6+2y=2 => 2y=-4 => y=-2. Substitute this value of y in the first equation and find x: x=6-2(-2) => x=10. The ordered pair (10, -2) is the solution of our system.


Check: {{{ system(2*10+4*(-2)=12, 4*10+16*(-2)=8)}}}

       {{{ system(20-8=12, 40-32=8)}}}

        {{{system(12=12, 8=8)}}}