<PRE><B>Question 427025</B>
A rectangular sheet of aluminum foil is 50cm long and20cm wide, and weighs 5.4 grams. Find the thickness of the aluminum foil in cm.

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Its volume = 50*20*t (t = thickness)
Using 2.7 gm/cc for the density of Al,
5.4 = 1000t*2.7
t = 5.4/2.700E3 cm
t = 2E-3 cm or 0.002 cm
= 0.02 mm
= 20 microns
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