Question 427006
There are three zeros, since it's a third degree polynomial (fundamental theorem of algebra).


Divide {{{P(x) = (2x^3 - x^2 - 13x - 6)/(x+2)}}} using either long or synthetic division. You should obtain {{{2x^2 - 5x - 3}}}. We find the other zeros of the function using the quadratic equation:


{{{x = (5 +- sqrt(25 + 24))/4 = (5 +- 7)/4}}} = 3 or -1/2. Hence, this polynomial factors to {{{(x-3)(x+1/2)}}} and P(x) is equal to {{{(x-3)(x+1/2)(x+2)}}}.