Question 426687
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Hi
Geometric Sequence:  {{{a[n] = a[1]*r^(n-1)}}}

1, -1/3, 1/9, -1/27, ....  r = -1/3   {{{a[n] = 1*(-1/3)^(n-1)}}}

6, 12, 24, 48, ...    r = 2     {{{a[n] = 6*(2)^(n-1)}}}

50, 25, 12.5, 6.25, ....   r = (1/2)  {{{a[n] = 50*(1/2)^(n-1)}}}