Question 426654
How can I solve the pythagorean theorem if a=2x b=x and c= 4 sqrt (5)
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{{{c^2 = a^2 + b^2}}}
{{{80 = 4x^2 + x^2 = 5x^2}}}
{{{x^2 = 16}}}
x = 4
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Actually, it's solving for x, not solving the Pythagorean Theorem.