Question 426567
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
find the standard form of the equation by completing the square
196x^2+9y^2+392x+54y-1487=0
 196(x+1)^2 -196 + 9(y+3)^2 -81 - 1487 = 0
  196(x+1)^2  + 9(y+3)^2 = 1764
  (x+1)^2/9  + 9(y+3)^2/196 = 1
 {{{ (x+1)^2/3^2  + 9(y+3)^2/14^2 = 1}}}
Elipse: a = 3 and b = 14  C(-1,-3)
{{{drawing(300,300,  -20,20,-20,20,  arc(-1,-3,6,28),
 grid(1),
circle(-1, -3,0.8),
graph( 300, 300, -20,20,-20,20))}}}