Question 426518
The cross sectional area of a rod = {{{(pi)r^2}}}
Therefore A = {{{(pi)(10)^2 = 314.16}}} mm^2
Convert the area to square meters: 314.16 mm^2*(1 m/1000 mm)^2 = 3.1416 x 10^-4
We are given S = 1 x 10^8, and L = 5 x 10^4
For the rod to withstand the load, we need the stress to be less than 1 x 10^8
Since S = L/A, we have S = 5 x 10^4/3.1416 x 10^-4 = 1.59 x 10^8 N/m^2.
This value is greater than the maximum stress of 1 x 10^8, so the rod will not withstand the load.