Question 426442
Solution;logx +log(x+16)=log36 because log base 6 of 36 is equal 2.
         Now base on the logarithm properties we write:

  log x(x+16)=log36 => x(x+16)=36 => {{{x^2+16x-36=0}}}

  The roots of this equation are: {{{x=(-16+- 4sqrt(7))/2}}}

  {{{ x=-8+- 2*sqrt(7)}}}

Answer: The solution set is the empty set because the two roots are negative.