Question 426461
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
what are the zeros in 
 3x^4+4x^3-21x^2-10x+24     |If x = 1 then 3+4-21+24 = 0
dividing the above by (x-1)results in:
 3x^3+7x^2-14x-24             |If x = 2 then 24+28-28-24 = 0
dividing the above by (x-2)results in:
 3x^2 + 13x +12
factoring
 (3x+4)(x+3)=0
 (3x+4)= 0  x = -4/3
  (x+3)=0   x = -3
the 4 'zeros' for x are: -3,-4/3,1,2