Question 426485
It's a little confusing the way you present it
Is it:
{{{log(2,.5^4)}}}
or is it
{{{(log(2,.5))^4}}}
I'm guessing it's the first one
The general rule is:
{{{ log(a^b) = b*log(a) }}}, so
{{{ log(2,.5^4) = 4*(log(2,.5))}}}
note that
{{{log(2,.5) = log(2,2^(-1))}}}
From the above rule, this is
{{{ (-1)*log(2,2) }}} so, the whole thing is:
{{{ 4*(-1)*log(2,2) = -4}}} answer