Question 426182
log2= .301 log5=.699
So, Please solve log(8/125)=

..
log(8/125)
=log 8-log125
=log2^3-log5^3
=3log2-3log5
=3(.301)-3(.699)
=.903-2.097=-1.194
ans:
log(8/125)=-1.194