Question 426225
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In the first place, you don't need clue 2 to solve the problem, although clue 2 does fit in the end.


If the probability of NOT spinning a 1 is 75%, then the probability of spinning a 1 must be 1 - 0.75 = 0.25 = 25%


Then since the probability of spinning a 2 is equal to the probability of spinning a 1, then the probability of spinning a 2 must also be 25%.


That leaves 50% for the third number whatever number that might be.


So even though the probability of spinning a 1 is the same as the probability of spinning a 2, each of these has a different probability than spinning the third number.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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