Question 425899
the average of the original 8 men is equal to x


this mans that the sum of their ages divided by the number of men = x


we get S/8 = x


we know that if we subtract (21 and 23) from the sum, and we add the ages of 2 other men, that the average age now becomes (x+2).


formula for this would be:


(S - 44 + y)/8 = (x+2)


y represents the sum of the ages of the 2 new men.


we have 2 equations:


S/8 = x and (S - 44 + y)/8 = (x+2)


if we multiply both sides of each equation by 8, then we get:


S = 8*x and S - 44 + y = 8*(x+2)


Since S = 8*x in the first equation we can susbtitute 8*x for S in the second equation to get:


8*x - 44 + y = 8*(x+2)


We simplify this by removing parentheses to get:


8*x - 44 + y = 8*x + 16


we subtract 8*x from both sides of the equation and we add 44 to both sides of the equation to get:


y = 60


y is the sum of the ages of the 2 new men.


their average age is 60/2 = 30


that should be the answer to your question.