<PRE><B>Question 425353</B>
A 280 ML solution is 20% salt.
 How much water should be added to make the solution 14% salt? 
:
Do it like this
Let w = amt of water required to accomplish this
:
Amt of salt does not change, only the percent salt changes
.20(280) = .14(w+280)
56 = .14w + 39.2
56 - 39.2 = .14w
16.8 = .14w
w = {{{16.8/.14}}}
w = 120 ml of water required
:
:
Check this
.20(280) = .14(120+280)
.20(280) = .14(400)
56 = 56</PRE>