Question 425200
Y/2-5y/6+1/3=1/2...Can you tell me how to solve this problem
Assuming the problem is:
{{{y/2}}} - {{{(5y)/6}}} + {{{1/3}}} = {{{1/2}}}
:
Multiply by 6
6*{{{y/2}}} - 6*{{{(5y)/6}}} + 6*{{{1/3}}} = 6*{{{1/2}}}
:
Cancel the denominators and you have
3y - 5y + 2 = 3
3y - 5y = 3 - 2
-2y = 1
y = {{{1/(-2)}}}
y = {{{-1/2}}}