Question 425152
Let {{{n}}} = number of nickels she has
Let {{{d}}} = number of dimes she has
given:
{{{ d = 5n }}}
{{{ 10d + 5n = 330 }}} (in cents)
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Use substitution
{{{10*5n + 5n = 330 }}}
{{{ 50n + 5n = 330 }}}
{{{ 55n = 330 }}}
{{{ 5n = 30 }}}
{{{ n = 6 }}}
and
{{{d = 5n}}}
{{{ d = 5*6}}}
{{{d = 30}}}
She has 6 nickels and 30 dimes