Question 424730
Solutions: 

6m + n = 11...................(1)

m-5n=38.......................(2)

From equation (2) we get,

m= 38+5n

Now substitute the value of m in equation(1) we get,

6(38 + 5n) + n = 11

228 + 30n +n =11

31n + 228 -228= 11-228

31n= -217
n= -217/31
n= -7

substitute the value of n in

m = 38 +5n
m= 38 + 5(-7)
m= 38 - 35
m= 3